13. The function y=-6sin (x) + C has a maximum value of 10. What is its minimum value? Explain your

answer.

Minimum value = - 2

Explanation:

For a function y = P + Qsinx

Maximum value is given by:

Max = P + |Q|

Minimum value is given by:

Min = P - |Q|

In the given question:

y = - 6sinx + C

Max = C + 6

It is given that Max = 10

10 = C + 6

C = 4

The minimum value, Min = C - 6

Min = 4 - 6

Min = - 2