Convert the equation of the circle below to standard form:

x2 + 2x + y2 + 6y = 15

A. (x + 2) 2 + (y + 6) 2 = 36

B. (x + 3) 2 + (y + 1) 2 = 25

C. (x + 1) 2 + (y + 3) 2 = 5

D. (x + 1) 2 + (y + 3) 2 = 25

Question

Steve Gallagher

History

3 January, 15:48

Convert the equation of the circle below to standard form:

x2 + 2x + y2 + 6y = 15

A. (x + 2) 2 + (y + 6) 2 = 36

B. (x + 3) 2 + (y + 1) 2 = 25

C. (x + 1) 2 + (y + 3) 2 = 5

D. (x + 1) 2 + (y + 3) 2 = 25

+4

Answers (1)

Know the Answer?

Abraham · Answer 1

The answer to your question is the letter D.

Explanation:

Equation of the circle

x² + 2x + y² + 6y = 15

-Group like terms

(x² + 2x) + (y² + 6y) = 15

-Complete perfect square trinomials

(x² + 2x + 1²) + (y² + 6y + 3²) = 15 + 1² + 3²

-Simplify

(x + 1) ² + (y + 3) ² = 15 + 9 + 1

-Equation in standard form

(x + 1) ² + (y + 3) ² = 25

Convert the equation of the circle below to standard form:x2 + 2x + y2 + 6y = 15A. (x + 2) 2 + (y + 6) 2 = 36B. (x + 3) 2 + (y + 1) 2 = 25C. (x + 1) 2 + (y + 3) 2 = 5D. (x + 1) 2 + (y + 3) 2 = 25

Convert the equation of the circle below to standard form:

x2 + 2x + y2 + 6y = 15

A. (x + 2) 2 + (y + 6) 2 = 36

B. (x + 3) 2 + (y + 1) 2 = 25

C. (x + 1) 2 + (y + 3) 2 = 5

D. (x + 1) 2 + (y + 3) 2 = 25