A student in Greece discovers a pottery bowl that contains 62% of its original amount of c-14. Find the age of the pottery bowl to the nearest year

For this problem, we use the formula for radioactive decay which is expressed as follows:

An = Aoe^-kt

where An is the amount left after time t, Ao is the initial amount and k is a constant.

We calculate as follows:

The half-life of C-14 is 5730 years:

An = Aoe^-kt

0.5 = e^-k (5730)

k = 1.21x10^-4

An = Aoe^-kt

.62 = e^-1.21x10^-4 (t)

t = 3951 years

The correct answer is 4780.