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Zechariah Kelly
Mathematics
14 May, 23:32
8x+4y = - 4
what is the slope and y intercept of the line
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Bernard Chan
14 May, 23:35
0
y = - 2x - 1; slope = - 2, y-intercept = (0, - 1)
Step-by-step explanation:
to get the slope and y intercept, you need to put the equation into slope-intercept form: y = mx + b
the term mx is the slope of the line, and b is the y-intercept
to do this, you need to solve for y, so get y by itself by subtracting 8x from the left side
8x + 4y = - 4
-8x. - 8x
4y = - 8x - 4
divide both sides by 4 to get y alone
4y/4 = y
-8x/4 = - 2x
-4/4 = - 1
y = - 2x - 1 is the final equation
the slope of the line is - 2 (also can be said as - 2/1), and the line intercepts the y-axis at (0,-1)
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Jasper Briggs
14 May, 23:39
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The y-intercept is y=-1
the slope is m=-2
Step-by-step explanation:
The general equation of the line is:
y = mx + b, where "m" represents the slope.
In this case, we need to divide the whole equation by 4 in order to get an equation similar to the general equation of the line:
8x + 4y = - 4, dividing the whole equation by 4 we get:
2x + y = - 1, solving for y we have: y = - 2x - 1. Then the slope is m=-2.
To find the y-intercept we need to make x=0
y = - 2 (0) - 1 = - 1
The y-intercept is y=-1
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