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8x+4y = - 4

what is the slope and y intercept of the line

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Answers (2)
  1. 14 May, 23:35
    0
    y = - 2x - 1; slope = - 2, y-intercept = (0, - 1)

    Step-by-step explanation:

    to get the slope and y intercept, you need to put the equation into slope-intercept form: y = mx + b

    the term mx is the slope of the line, and b is the y-intercept

    to do this, you need to solve for y, so get y by itself by subtracting 8x from the left side

    8x + 4y = - 4

    -8x. - 8x

    4y = - 8x - 4

    divide both sides by 4 to get y alone

    4y/4 = y

    -8x/4 = - 2x

    -4/4 = - 1

    y = - 2x - 1 is the final equation

    the slope of the line is - 2 (also can be said as - 2/1), and the line intercepts the y-axis at (0,-1)
  2. 14 May, 23:39
    0
    The y-intercept is y=-1

    the slope is m=-2

    Step-by-step explanation:

    The general equation of the line is:

    y = mx + b, where "m" represents the slope.

    In this case, we need to divide the whole equation by 4 in order to get an equation similar to the general equation of the line:

    8x + 4y = - 4, dividing the whole equation by 4 we get:

    2x + y = - 1, solving for y we have: y = - 2x - 1. Then the slope is m=-2.

    To find the y-intercept we need to make x=0

    y = - 2 (0) - 1 = - 1

    The y-intercept is y=-1
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