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28 February, 03:31

In the equation, f (x) = 6x² + 8x which value (s) for x make f (x) = 0 true?

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  1. 28 February, 03:55
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    0 & - 4/3.

    Step-by-step explanation:

    If f (x) = 0, then 6x^2 + 8x=0. Next, factoring out an x, we get x (6x+8) = 0. So either x=0 or 6x+8=0. In our second equation, x=-4/3.
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