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Fernanda Nicholson
Mathematics
28 July, 01:14
Find f (t-3) for f (*) = 4x^2-8*+4
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Jadiel Zhang
28 July, 01:23
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4t^2-32t+64=4 (t^2-8x+16)
Step-by-step explanation:
f (x) = 4x^2-8x+4
f (t-3) = 4 (t-3) ^2 - 8 (t-3) + 4=
4 (t^2-2*t*3+9) - 8t+24+4=
4 (t^2-6t+9) - 8t+28=
4t^2-24t+36-8t+28=
4t^2-32t+64=4 (t^2-8x+16)
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