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16 December, 18:53

A container holds a combination of dimes and nickels. There are 200 coins in all, and their total value is $16.30. The system of equations models this situation, where x is the number of dimes and y is the number of nickels.

x+y=200

0.1x+0.05y=16.3

How many dimes and nickels are in the container?

A.

126 dimes and 74 nickels

B.

132 dimes and 68 nickels

C.

84 dimes and 116 nickels

D.

112 dimes and 88 nickels

+5
Answers (1)
  1. 16 December, 19:15
    0
    X+y=200

    x=200-y

    0.1x+0.05y=16.3

    0.1 (200-y) + 0.05y=16.3

    20-0.1y+0.05y=16.3

    -0.05y=16.3-20

    -0.05y=-3.7

    0.05y=3.7

    y=3.7•100/5

    y=370/5

    y=74

    x=200-y

    x=126

    A. 126 dimes and 64 nickels
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Home » Mathematics » A container holds a combination of dimes and nickels. There are 200 coins in all, and their total value is $16.30. The system of equations models this situation, where x is the number of dimes and y is the number of nickels. x+y=200 0.1x+0.05y=16.
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