The equation 2x^2+12x=4 is written in the form of 2 (x-p) ^2+q=0. what is the value of q?

1) Factor out the coefficient 2: 2x^2+12x=4 = > 2 (x^2 + 6x) = 4

2) Complete the square of x^2 + 6x: x^2 + 6x + 9 - 9. Then:

2 (x^2 + 6x + 9 - 9) = 4

3) Rewrite the square as the square of a binomial:

2 ([x+3]^2 - 9) = 4, or

2 ([x+3]^2) = 22, or

2 ([x+3]^2) - 22 = 0

The value of q is - 22.