What is the integral of sqrt (1-cosx) ?

we can apply the rules of trigonometry to determine the integral of the function: The exponent is added by 1 and the function is multiplied by the reciprocal of the added power. Hence,

y' = sqrt (1-cosx) y = (2/3) (1 - cos x) ^ (3/2) * (x - sin x) y = (2/3) * (x - sin x) (1 - cos x) ^ (3/2)