Factor the Trinomial:

2a^2 + 3a + 1

Try "factoring by grouping."

The binomial factors of 2a^2 + 3a + 1 must start with a and 2a respectively, so that the product of these first terms is 2a^2. Also note that a and 2a must add up to 3a. They do.

Then 2a^2 + 3a + 1 = (2a+1) (a+1).

2a^2 + 3a + 1

= 2a^2 + 2a + a + 1

= 2a (a + 1) + 1 (a + 1) (a + 1) is common)) so it is

= (2a + 1) (a + 1) (answer)