20 subtracted from three times a number is 6 more than the number

20 subtracted from three times a number is 6 more than the number. Then the number is 13

Solution:

Given statement is:

20 subtracted from three times a number is 6 more than the number

We can translate the sentence into algebraic expression

Let "a" be the unknown number

Then,

20 subtracted from three times "a" is 6 more than "a"

Which means,

3a - 20 = 6 + a

3a - a = 6 + 20

2a = 26

Divide both sides by 2

a = 13

Thus the number is 13