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David Figueroa
Mathematics
26 November, 23:19
Factor completely 12a3d2 - 6ad3
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Nola Merritt
26 November, 23:27
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12a³d² - 6ad³ = 6ad² (2a² - d)
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Ezekiel Hensley
26 November, 23:29
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GCD (12,6) = 6
GCD (a³, a) = a
GCD (d², d³) = d²
Then 12a³d² - 6ad³ = 6. a. d² (2a - d)
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