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Mathematics
20 November, 22:19
How do you solve this? r^2+32=12r
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Jovanny
20 November, 22:27
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r = {-8, - 4}
Step-by-step explanation:
Simplifying
r2 = - 32 + - 12r
Solving
r2 = - 32 + - 12r
Solving for variable 'r'.
Reorder the terms:
32 + 12r + r2 = - 32 + - 12r + 32 + 12r
Reorder the terms:
32 + 12r + r2 = - 32 + 32 + - 12r + 12r
Combine like terms: - 32 + 32 = 0
32 + 12r + r2 = 0 + - 12r + 12r
32 + 12r + r2 = - 12r + 12r
Combine like terms: - 12r + 12r = 0
32 + 12r + r2 = 0
Factor a trinomial.
(8 + r) (4 + r) = 0
Subproblem 1
Set the factor ' (8 + r) ' equal to zero and attempt to solve:
Simplifying
8 + r = 0
Solving
8 + r = 0
Move all terms containing r to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + - 8 + r = 0 + - 8
Combine like terms: 8 + - 8 = 0
0 + r = 0 + - 8
r = 0 + - 8
Combine like terms: 0 + - 8 = - 8
r = - 8
Simplifying
r = - 8
Subproblem 2
Set the factor ' (4 + r) ' equal to zero and attempt to solve:
Simplifying
4 + r = 0
Solving
4 + r = 0
Move all terms containing r to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + - 4 + r = 0 + - 4
Combine like terms: 4 + - 4 = 0
0 + r = 0 + - 4
r = 0 + - 4
Combine like terms: 0 + - 4 = - 4
r = - 4
Simplifying
r = - 4
Solution
r = {-8, - 4}
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