If the angles are represented in degrees, find both angles: / cos (3x+13) = / sin (2x+42) cos (3x+13) = sin (2x+42)

cos34°

sin56°

Step-by-step explanation:

Sin (2x+42) = sin90 - (3x+13)

Sin (2x+42) = sin (90-13-3x)

Sin (2x+42) = sin (77-3x)

2x + 42 = 77-3x

5x. = 35

X = 7

If x = 7

cos (3x+13) = cos ((3*7) + 13)

cos (3x+13) = cos (21+13)

cos (3x+13) = cos34

And

sin (2x+42) = sin ((2*7) + 42)

sin (2x+42) = sin (14+42)

sin (2x+42) = sin56