Kayla and Jody are working at a station. They have been given four cards with four different functions on them.

Function A Function B Function C Function D

f (x) = 2^x+1 f (x) = 2 (x-1) ^2 f (x) = 2x+2 f (x) = 2x^2-1

Kayla states that Function D always exceeds the other functions. Jody doesn't think Kayla's statement is true. Which values of x disproves her claim? Explain your reasoning.

Question

29 October, 03:43

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Answers (1)

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Blackjack · Answer 1

If x=0, then f (x) = - 1. The value of - 1 makes Function D less than any of the other functions.

f (0) = 2 (0^2) - 1

=2 (0) - 1

=0-1

=-1