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9 March, 00:31

A cylindrical tank of radius 5 ft and height 9 ft is two-thirds filled with water. Find the work required to pump all the water over the upper rim.

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  1. 9 March, 00:35
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    130.826 kilojoules

    Step-by-step explanation:

    The Work required to pump water = pgV

    Where, p = density of water = 1000 kg/m³

    g = acceleration due to gravity = 9.81ms-¹

    V = volume of water

    Since, radius r = 5 ft and height h = 9ft

    Volume of water in the cylindrical tank = (2/3) πr²h

    V = (2/3) π * 5²*9 = 471.24 ft³ = 471.24 * 0.0283m³ = 13.336m³

    Work required = 1000*9.81*13.336

    W = 130.826 KJ

    Therefore, the work required to pump water 2/3 of the volume of the cylindrical tank = 130.826 kilojoules.
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