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21 January, 05:51

If the sides of a triangle have measures 3x + 4, 6x - 1 and 8x + 2, find all possible values of x.

Question 12 options:

a)

x > - 4/3

b)

0 < x < 1/6

c)

1/6 < x < 3/11

d)

x > 0

+2
Answers (2)
  1. 21 January, 05:52
    0
    Answer: x>-4/3

    Step-by-step explanation:All sides must be greater of zero:

    3x+4>0

    3x> - 4 Divide with 3

    x> - 4/3

    6x-1>0

    6x>1 Divide with 6

    x>1/6

    8x+2>0

    8x> - 2 Divide with 8

    x> - 2/8

    x> - 1/4

    Least of that numbers is - 4/3 = - 1.3333

    x> - 4/3 is solution
  2. 21 January, 05:52
    0
    Answer: x>-4/3 is correct.
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