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7 September, 17:11

Write the first five terms of the geometric sequence if the nth term is given by 36 (1/3) ^n-1

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Answers (2)
  1. 7 September, 17:20
    0
    36, 12, 4, 4/3, 4/9.

    Step-by-step explanation:

    We find each term by substituting the sequence number.

    So the first term (where n = 1)

    = 36 (1/3) ^ (1-1)

    = 36 (1/3) ^0

    = 36 * 1

    = 36.

    The second term is 36 (1/3) ^ (2-1) = 36 * 1/3

    = 12.

    We can find subsequent terms by just multiplying the previous term by 1/3 so the third term = 12 * 1/3 = 4.

    So the first 5 terms are 36, 12, 4, 4/3, 4/9.
  2. 7 September, 17:22
    0
    G1=36, G2=12, G3=4, G4=4/3, G5=4/9

    Step-by-step explanation:

    Since the nth term is given by;

    Gn = 36 (1/3) ^n-1, then, substitute the values of n as 1,2,3,4 and 5 to get the values of G1, G2, G3, G4 and G5 respectively.

    G1=36 (1/3) ^1-1 = 36

    G2 = 36 (1/3) ^2-1 = 12

    G3 = 36 (1/3) ^3-1 = 4

    G4 = 36 (1/3) ^4-1 = 4/3

    G5 = 36 (1/3) ^5-1=4/9
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