What is the range of the function y=

= VX+5?

Oy2-5

Oy20

O yzv5

Oy25

A) y² - 5

The range of the given function x = y² - 5

Step-by-step explanation:

Explanation:-

Given f (x) = √x + 5

Let y = f (x) = √x + 5

y = √x + 5

squaring on both sides, we get

⇒ y² = x + 5

⇒ x = y² - 5

The range of the given function x = y² - 5