The ages of three brothers are consecutive even integers. Three times the age of the youngest brother exceeds the oldest brothers age by 48 years. What is the age of the youngest brother?

The age of youngest brother is 26 years old

Solution:

Let the three consective even integers be x, x + 2 and x + 4

Let the youngest brother age = x

Let the oldest brother age = x + 4

Let the another brother (middle one) age = x + 2

Three times the age of the youngest brother exceeds the oldest brothers age by 48 years

Therefore, we can frame a equation as:

Three times age of the youngest brother = Age of oldest brother + 48

three times x = x + 4 + 48

3x = x + 4 + 48

3x - x = 52

2x = 52

x = 26

Thus the age of youngest brother is 26 years old