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Mathematics
16 May, 15:40
7x+3/x2-8x+15+3x/x-5=1/3-x
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Valeria Trevino
16 May, 16:00
0
Combine like terms
(3/x^2) + 7x - 8x + 15 + 3x/x - 5 = (1/3) - x
The x will cancel out of 3x/x term leaving just x. Move all x's to left of equal sign and all constants to the right.
(3/x^2) + 7x-8x+x = - 15-3+5 + (1/3)
(3/x^2) = - 13 + (1/3)
Convert - 13 to a fraction - - 39/3 and add to 1/3
(3/x^2) = - 38/3
Multiply both sides by x^2.
3 = (-38/3) x^2
Multiply both sides by (-3/38)
(-9/38) = x^2
Take square root of both sides
Sq rt (-9/38) = x
Bring an i out from under the sq rt to get rid of the negative sign.
3i / (sq rt 38) = x
Multiply top and bottom by sq rt 38 to get it off the denominator.
3i (sq rt 38) / 38 = x
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