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24 May, 07:48

Find the slope-intercept form of the equation of the line that passes through

(-5, 3) and is parallel to 12x - 3y = 10.

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  1. 24 May, 07:57
    0
    Step-by-step explanation:

    12x - 3y = 10

    -3y = - 12x + 10

    y = 4x - 10/3 ... the slope here is 4

    parallel lines will have the same slope

    y = mx + b

    slope (m) = 4

    (-5,3) ... x = - 5 and y = 3

    now we sub and find b, the y int

    3 = 4 (-5) + b

    3 = - 20 + b

    3 + 20 = b

    23 = b

    so ur equation is : y = 4x + 23 <==
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