Ask Question
7 August, 10:47

What is the growth factor of y=34*4^x, the initial amount of y=15*3^x and the decay factor of y=17*0.2^x

+1
Answers (1)
  1. 7 August, 11:05
    0
    So the growth factor is the base of the exponential term, so the base of y = 34 * 4^x is 4.

    the initial amount is the amount at x = 0

    y = 15 * 3^xy = 15 * 3^0y = 15 * 1y = 15 is the initial amount

    the decay factor of y=17*0.2^x is same as the growth factor, it is 0.2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the growth factor of y=34*4^x, the initial amount of y=15*3^x and the decay factor of y=17*0.2^x ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers