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Warren Hamilton
Mathematics
27 August, 00:30
How do I show work for 5 - (a-4) = 3 (a+2)
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Harper Fry
27 August, 00:51
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Here is how I would show the work for this problem
5 - (a-4) = 3 (a+2)
5-a+4 = 3*a+3*2
5-a+4 = 3a+6
-a+9 = 3a+6
-a+9+a = 3a+6+a
9 = 4a+6
9-6 = 4a+6-6
3 = 4a
4a = 3
4a/4 = 3/4
a = 3/4
So the solution is the fraction a = 3/4 (in decimal form 0.75)
Let me know if you have any questions or issues with any of the steps shown above. It's a lot to take in so feel free to ask about anything really.
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Danielle Santiago
27 August, 00:51
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5 - (a-4) = 3 + (a+2)
distribute invible - 1
5-a+4=4+a+1
9-a=a+5
add a to both sides
9=2a+5
minus 5 both sides
4=2a
divide by 2 both sides
2=a
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