Given cosx = 4/5 when (3π/2) < x<2π find sin2x

A. 18/24

B - 18/25

C.-1/5

D. - 24/25

D - 24/25

Step-by-step explanation:

sin (2x) = 2sin (x) cos (x)

cos (x) = ⅘

sin² (x) = 1 - cos² (x) = 1 - (⅘) ²

sin² (x) = 9/25

sin (x) = - ⅗

(Because 4th quadrant)

sin (2x) = 2 (-⅗) (⅘)

= - 24/25