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19 February, 22:00

Given cosx = 4/5 when (3π/2) < x<2π find sin2x

A. 18/24

B - 18/25

C.-1/5

D. - 24/25

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Answers (1)
  1. 19 February, 22:16
    0
    D - 24/25

    Step-by-step explanation:

    sin (2x) = 2sin (x) cos (x)

    cos (x) = ⅘

    sin² (x) = 1 - cos² (x) = 1 - (⅘) ²

    sin² (x) = 9/25

    sin (x) = - ⅗

    (Because 4th quadrant)

    sin (2x) = 2 (-⅗) (⅘)

    = - 24/25
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