Ask Question
15 February, 12:37

Write y = 2x^2 + 8x + 3 in vertex form.

y = 2 (x - 2) ^2 - 5

y = (x - 4) ^2 + 3

y = 2 (x + 2) ^2 - 5

y = (x + 4) ^2 + 3

+4
Answers (1)
  1. 15 February, 12:45
    0
    y = 2 (x + 2) ^2 - 5

    Step-by-step explanation:

    When y = ax^2 + bx + c is written in vertex form, it becomes ...

    y = a (x + b / (2a)) ^2 + (c - b^2 / (4a))

    The constant term in the squared binomial is b / (2a) = 8 / (2 (2)) = + 2. Only one answer choice matches:

    y = 2 (x + 2) ^2 - 5
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Write y = 2x^2 + 8x + 3 in vertex form. y = 2 (x - 2) ^2 - 5 y = (x - 4) ^2 + 3 y = 2 (x + 2) ^2 - 5 y = (x + 4) ^2 + 3 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers