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Sydney Baird
Mathematics
19 September, 00:19
Solve for x: 2logx=log64
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Levi Burns
19 September, 00:45
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2logx = log64
2logx = log (2) ⁶
2logx = 6. log (2)
logx = 3log (2)
logx=log (2) ³ = = = > x = 2³ & x = 8
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