Which equation has the same solution as x^2-6x-12=0?

1) (x+3) ^2=21 2) (x-3) ^2=2

3) (x+3) ^2=3 4) (x-3) ^2=3

I see that you complete the square

basically

for

ax^2+bx+c=0

isolate the x terms

(ax^2+bx) + c=0

factor out a if a is not equal to 1

take 1/2 of b and square it and add posotive and negative inside

so

x^2-6x-12=0

move c aside

(x^2-6x) - 12=0

first term iss 1 do don't undistribute

take 1/2 of - 6 and square it (-6/2=-3, (-3) ^2=9)

add negative and positive

(x^2-6x+9-9) - 12=0

factor perfect square

((x-3) ^2-9) - 12=0

(x-3) ^2-9-12=0

(x-3) ^2-21=0

add 21 both sides

(x-3) ^2=21

yah, answer is 2nd one

x² - 6x - 12 = 0

+ 12 + 12

x² - 6x = 12

x² - 6x + 9 = 12 + 9

x² - 3x - 3x + 9 = 21

x (x) - x (3) - 3 (x) + 3 (3) = 21

x (x - 3) - 3 (x - 3) = 21

(x - 3) (x - 3) = 21

(x - 3) ² = 21

The answer is 2.