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4 February, 10:51

Cylinder A has radius r and height h. Cylinder B has radius 4r and height 4h. How many times greater is the surface area of Cylinder B than the surface area of Cylinder A?

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  1. 4 February, 11:01
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    Surface area of cylinder A = 2πr²+2πrh

    Surface area of cylinder B = 2π (4r) ²+2π (4r) (4h) = 16 * (2πr²) + 16 * (2πrh) =

    =16 (2πr²+2πrh) = 16 (Surface area of cylinder A)

    Surface area of cylinder B=16 (Surface area of cylinder A).

    So

    the surface area of Cylinder B is 16 times greater than the surface area of Cylinder A.
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