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19 November, 17:36

Let f (x) = x2+6x-16 . Enter the x-intercepts of the quadratic function in the boxes. and

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  1. 19 November, 17:55
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    x = - 8, x = 2

    Step-by-step explanation:

    Given

    f (x) = x² + 6x - 16

    To find the x - intercepts equate f (x) to zero, that is

    x² + 6x - 16 = 0 ← in standard form

    (x + 8) (x - 2) = 0 ← in factored form

    Equate each factor to zero and solve for x

    x + 8 = 0 ⇒ x = - 8

    x - 2 = 0 ⇒ x = 2
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