If 4z + 3 = 35 and 2z+3y=73 what does y equal

Answer: y = 19

Step-by-step explanation: First, let's solve for z in our first equation. To solve for z, we must first isolate the term containing z which in this problem is 4z.

Since 3 is being added to 4z, we subtract 3 from both sides of the equation to isolate the 4z. On the left, the + 3 and - 3 cancel out and on the right, 35 - 3 is 32 so we have 4z = 32. Now we can finish things off by just dividing both sides of the equation by 4. On the left the 4's cancel and on the right, 32 divided by 4 is 8 so z = 8.

Now in order to solve for y, we need to solve the second equation but we will plug the value of z into the second equation. So we have 2 (8) + 3y = 73. We can simplify on the left side to get 16 + 3y = 73.

Now we want to subtract 16 from both sides of the equation in order to get our y-term by itself. On the left side, 16 - 16 cancels and we have 3y. On the right side we have 73 - 16 which simplifies to 57. Now we have the equation 3y = 57 and we want to get y by itself and we do that by dividing both sides of the equation by 3 and we get y = 19.

So the value of y in this problem is 19.

y = 19

Step-by-step explanation:

Solve the first equation for z

4z + 3 = 35 (subtract 3 from both sides)

4z = 32 (divide both sides by 4)

z = 8

Substitute z = 8 into the second equation and solve for y

2 (8) + 3y = 73, that is

16 + 3y = 73 (subtract 16 from both sides)

3y = 57 (divide both sides by 3)

y = 19