John has 48 square centimeter tiles he wants to use to create a mosaic. He wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width.

Which equation could John solve to find w, the greatest width in centimeters he can use for the mosaic?

w (w - 2) = 48

w (w + 2) = 48

2w (w - 2) = 48

2w (w + 2) = 48

Question

Valentine

Mathematics

10 February, 01:48

John has 48 square centimeter tiles he wants to use to create a mosaic. He wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width.

Which equation could John solve to find w, the greatest width in centimeters he can use for the mosaic?

w (w - 2) = 48

w (w + 2) = 48

2w (w - 2) = 48

2w (w + 2) = 48

+2

Answers (1)

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Chapman · Answer 1

The correct answer for the question that is being presented above is this one: "w (w + 2) = 48." John has 48 square centimeter tiles he wants to use to create a mosaic. He wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width.

Let w = width

Let (w+2) = length

Area = w (w+2).