Solving systems of equations using substitution 4g-2h = - 6 13=h - 4g

Solve for 1 variable

actually, simplify the top equation by dividing both sides by 2 first

2g-h=-3

2nd equation

solve for h

add4g both sides

h=13+4g

sub 13+4g for h in other equation

2g-h=-3

2g - (13+4g) = - 3

2g-13-4g=-3

-13-2g=-3

add 13 both sides

-2g=10

divide - 2

g=-5

sub back

h=13+4g

h=13+4 (-5)

h=13-20

h=-7

g=-5

h=-7

Solve by substitution

- - h=4g + 13

4g-2 (4g+13) = - 6

4g - 8g - 26 = - 6

-4g - 26 = - 6

-4g = 20

g = - 5

then plug in value for g into either equation to solve for h

h - 4 (-5) = 13

h+20 = 13

h = - 7