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Ainsley Townsend
Mathematics
19 February, 07:03
A8 = 40 and a13 = - 10, find a1 and d
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Esparza
19 February, 07:30
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A term in an arithmetic progression is given by the formula a1 + (n-1) d
Thus; a8 = a1 + 7d = 40
a13 = a1 + 12 d = - 10
Solving them simultaneously;
a1 + 7d = 40
a1 + 12d = - 10 subtracting the two equations
-5d = 50
d = - 10
a1 = 40 - (7 * - 10)
= 110
Therefore; a1 = 110 and d = - 10
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