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14 June, 20:28

What is the sum of the geometric sequence 8, 15, 22 ..., if there are 26 terms?

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  1. 14 June, 20:43
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    a₂-a₁=15-8=7

    a₃-a₂=22-15=7

    d=7

    aₙ=a₁+d (n-1)

    a₂₆=8+7 * (26-1) = 8+7*25=183

    S₂₆ = (a₁+a₂₆) * 26/2 = (8+183) * 26/2=2483
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