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Kellen Hester
Mathematics
6 November, 12:30
What is the sum of the geometric sequence 8, 15, 22 ..., if there are 26 terms?
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Omar Lopez
6 November, 13:34
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a₂-a₁=15-8=7
a₃-a₂=22-15=7
d=7
aₙ=a₁+d (n-1)
a₂₆=8+7 * (26-1) = 8+7*25=183
S₂₆ = (a₁+a₂₆) * 26/2 = (8+183) * 26/2=2483
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