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Vivian
Mathematics
28 December, 12:00
Factor 4m^2 + 16m+15
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Colt
28 December, 12:03
0
Split the second term in 4m^2 + 16m + 15 into two terms
4m^2 + 10m + 6m + 15
Factor out the common terms in the first two terms, then in the last two terms
2m (2m + 5) + 3 (2m + 5)
Factor out the common term 2m + 5
(2m + 5) (2m + 3)
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Rylie Foley
28 December, 12:30
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(2m + 5) (2m + 3) is the fully factored form of the trinomial.
4m^2 + 16m + 15
With the way the trinomial is, we cannot factor it in it's current state.
We must check to see if splitting the middle term is possible.
List factors of 60
1 * 60
-1 * - 60
2 * 30
-2 * - 30
3 * 20
-3 * - 20
4 * 15
-4 * - 15
5 * 12
-5 * - 12
6 * 10 (this digits satisfy the criteria for splitting the middle term.)
Split the middle term.
4m^2 + 6m + 10m + 15
Group the polynomials in terms of 2.
(4m^2 + 6m) + (10m + 15)
Factor each binomial.
2m (2m + 3) + 5 (2m + 3)
Rearrange the binomials.
(2m + 5) (2m + 3)
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