Solve the following two equations using elimination: x y=10 x-y=6

A. (4,6)

B. (8,4)

C. (8,2)

D. (2,8)

C. (8,2)

x + y = 10

x - y = 6

2x = 16

2x / 2 = 16 / 2

x = 8

x - y = 6

8 - y = 6

- y = 6 - 8

- y = - 2

-y / - 1 = - 2 / - 1

y = 2

To check:

x + y = 10; 8 + 2 = 10; 10 = 10

x - y = 6; 8 - 2 = 6; 6 = 6

Answer=C (8,2)

I'm assuming you meant x+y=10 and x-y=6

To solve for x and y, let's look at our options ...

a. (4,6)

b. (8,4)

c. (8,2)

d. (2,8)

Now we need to find one of the ordered pairs with a sum of 10

a. (4,6)

b. (8,4)

c. (8,2)

d. (2,8)

Both the ordered pairs of c and d have a sum of 10. Now lets plug both into the x-y=6 equation and see what we get ...

c. (8,2) 8-2=6

d. (2,8) 2-8=-6

The answer is C