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12 July, 23:25

Find the sum of the sequence 37+38+39+40 + ... 130

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  1. 12 July, 23:27
    0
    First, you have to calculate the number in the sequence

    an = a + (n-1) d

    130 = 27 + (n-1) 1

    130-27 = n-1

    103+1 = n

    n = 104

    Now, calculating for sum (Sn)

    Sn = n/2 (a+an) = 104/2 (37+130) = 52 (167) = 8684
  2. 12 July, 23:37
    0
    The sum is of37+38+39+40 + ... 130 is 154.13
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