What are the solutions to the quadratic equation of 2x^2-16x+32=0? and how would i solve this?

Divide first the given quadratic equation by 2 giving us,

x² - 8x + 16 = 0

The additive inverse of the second term of the equation is the sum of the roots and their product is constant or the third term. Let a and b be the roots of the equation such that,

a + b = 8

ab = 16

The values for a and b are both 4. Therefore, the roots are x = 4 and x = 4.