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5 October, 23:47

A triangle has an area of 1102 m², and two of the sides of the triangle have lengths 60 m and 56 m. find the angle included by these two sides.

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  1. 5 October, 23:57
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    A = (1/2) * a*b*sin (C)

    1102 m^2 = (1/2) * (60 m) * (56 m) * sin (C)

    2*1102 / (60*56) = 551/840 = sin (C)

    C = arcsin (551/840) ≈ 41°
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