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12 October, 14:48

A 50% antifreeze solution is to be mixed with an 80% antifreeze solution to get 180 liters of a 75% solution. How many liters of the 50% solution and how many liters of the 80% solution will be used?

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  1. 12 October, 15:03
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    Step-by-step explanation:

    If x is the volume of 50% solution and y is the volume of 80% solution, then the total volume is:

    x + y = 180

    And the total amount of antifreeze is:

    0.50 (x) + 0.80 (y) = 0.75 (180)

    0.5x + 0.8y = 135

    Solving the system of equations:

    0.5x + 0.8 (180 - x) = 135

    0.5x + 144 - 0.8x = 135

    9 = 0.3x

    x = 30

    y = 180 - x

    y = 150

    You need 30 gallons of 50% solution and 150 gallons of 80% solution.
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