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22 September, 15:33

A merchant wishes to blend 200 pounds of coffee worth $3.20 a pound from two mixtures: one at $3.00 a pound and the other at $3.25 a pound. How many pounds of each mixture should he use?

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  1. 22 September, 15:54
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    X pounds of $3

    y pounds of $3.25

    x+y = 200

    300x + 325y = 320*200

    300x + 325y = 64000

    x+y = 200

    300x + 325y = 64000

    Solve by eliminating

    Multiply top one w/-300

    -300y = 60000

    325y=64000

    25y = 4000

    y = 160 then

    x + 160 = 200

    x = 40

    So the mixture has;

    40 pounds of $3 coffee

    160 pounds of $3.25 coffee
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