6x + 3y = 9

2x + 3y = 1

Solve the system of equations.

A)

x = 2, y = - 1

B)

x = - 1, y = 2

C)

x=1/2, y=3

D)

x=3, y=-1/2

A

Step-by-step explanation:

Given the 2 equations

6x + 3y = 9 → (1)

2x + 3y = 1 → (2)

Subtracting the 2 equations term by term eliminates the y - term

Subtract (2) from (1) term by term, that is

(6x - 2x) + (3y - 3y) = 9 - 1

4x = 8 (divide both sides by 4)

x = 2

Substitute x = 2 into either of the 2 equations and evaluate for y

Substituting into (2)

2 (2) + 3y = 1

4 + 3y = 1 (subtract 4 from both sides)

3y = - 3 (divide both sides by 3)

y = - 1

The solution is x = 2, y = - 1 → A