For a proof by mathematical induction of for every naturalnumber the base case should be n =

Question

Tyler Wang

Mathematics

26 July, 16:07

For a proof by mathematical induction of for every naturalnumber the base case should be n =

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Wendy Hudson · Answer 1

The base case over the set of natural numbers would be n=1.

Step-by-step explanation:

The base case is for the first number in the set for which we are trying to prove something about a relation.

So the first number in the set of natural numbers is 1 since the natural numbers are {1,2,3,4,5, ... }.