The perimeter of a college athletic field is 100 meters and the length is 12 m more than the width. Find the length and width.

Length (L) : w + 12

width (w) : w

Perimeter (P) = 2L + 2w

100 = 2 (w + 12) + 2 (w)

100 = 2w + 24 + 2w

100 = 4w + 24

76 = 4w

19 = w

Length (L) : w + 12 = (19) + 12 = 31

Answer: width = 19 m, length = 31 m