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3 January, 03:50

You have 7 red, 5 blue, and 3 green MnM's left in a bag. What is the probability of randomly pulling out 2 green? (The first MnM is not replaced back into the bag because you ate it) Express answer as a fraction in simplest form. Explain.

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  1. 3 January, 03:54
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    Total = 7 + 5 + 3 = 15

    Green = 3

    Red = 7

    P (two green) = (3/15) (2/14) = 1/35

    P (two red) = (7/15) (6/14) = 1/5

    Answer: P (two green) = 1/35; P (two red) = 1/5
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