Ask Question
21 March, 09:04

A newspaper carrier has $7.10 in change. He has nine more quarters than dimes but three times as many nickels as quarters. How many coins of each type does he have?

+2
Answers (1)
  1. 21 March, 09:12
    0
    Let q represent the number of quarters he has. Then q-9 is the number of dimes, and 3q is the number of nickels. His total change is ...

    0.25q + 0.10 (q-9) + 0.05 (3q) = 7.10

    0.50q - 0.90 = 7.10

    q = (7.10 + 0.90) / 0.50 = 16

    The carrier has 16 quarters, 7 dimes, and 48 nickels.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A newspaper carrier has $7.10 in change. He has nine more quarters than dimes but three times as many nickels as quarters. How many coins ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers