Solve the triangle.

a = 10, b = 23, C = 95°

Select one:

a. c ≈ 25.1, A ≈ 26.8°, B ≈ 58.2°

b. c ≈ 25.1, A ≈ 22.8°, B ≈ 62.2°

c. c ≈ 25.9, A ≈ 22.8°, B ≈ 62.2°

d. c ≈ 25.9, A ≈ 59.2°, B ≈ 25.8°

Question

Mandy

Mathematics

18 May, 08:58

Solve the triangle.

a = 10, b = 23, C = 95°

Select one:

a. c ≈ 25.1, A ≈ 26.8°, B ≈ 58.2°

b. c ≈ 25.1, A ≈ 22.8°, B ≈ 62.2°

c. c ≈ 25.9, A ≈ 22.8°, B ≈ 62.2°

d. c ≈ 25.9, A ≈ 59.2°, B ≈ 25.8°

+1

Answers (1)

Know the Answer?

Donald Bailey · Answer 1

Given 2 sides and 1 included angle, the area of a triangle can be solved using the formula:

Area = ab (sin C) / 2

Substituting the given values:

Area = 10 * 23 * (sin 95) / 2

Area = 114.56 sq. units

Solve the triangle.a = 10, b = 23, C = 95°Select one:a. c ≈ 25.1, A ≈ 26.8°, B ≈ 58.2°b. c ≈ 25.1, A ≈ 22.8°, B ≈ 62.2°c. c ≈ 25.9, A ≈ 22.8°, B ≈ 62.2°d. c ≈ 25.9, A ≈ 59.2°, B ≈ 25.8°

Solve the triangle.

a = 10, b = 23, C = 95°

Select one:

a. c ≈ 25.1, A ≈ 26.8°, B ≈ 58.2°

b. c ≈ 25.1, A ≈ 22.8°, B ≈ 62.2°

c. c ≈ 25.9, A ≈ 22.8°, B ≈ 62.2°

d. c ≈ 25.9, A ≈ 59.2°, B ≈ 25.8°