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19 December, 16:38

According to a government commission, 70% of all the nation's households have vcrs. in a random sample of 15 households, what is the probability that have at least 13 vcrs? round to four decimal places.

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  1. 19 December, 16:49
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    Number of trials, n = 15

    Expected success, r = 13

    Probability of having a VCR, p = 70% = 0.7

    Probability of not having a VCR, q = 1 - p = 0.3

    According to the binomial distribution, the probability of 13 out of 15 households having a VCR is

    ₁₅C₁₃ p¹³ q¹⁵⁻¹³

    = [15! / (13!2!) ] * (0.7¹³) * (0.3²)

    = 0.0916

    Answer: 0.0916 (or 9.16%)
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