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5 August, 07:11

A series consists of some numbers such that the summation of the divisors of any number of that series is 1 less than twice of that number. For example, the divisors of 4 are 1,2 and 4 and the sum is 7. If the numbers of this sequence are arranged in ascending order then what is the 9th term?

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  1. 5 August, 07:31
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    The 9th term of the series is 256

    Step-by-step explanation:

    Here we have the numbers as follows

    1, 2, 4 from we have;

    1 = The first term of the series

    2 = The second term of the series

    4 = The third term of the series

    From the definition of the series, the sum of the factors is 1 less than twice the number, therefore, since 4 satisfies all the conditions, we observe that;

    4*2*1 = 8 also satisfies all the conditions, hence we have;

    8 = The fourth term of the series

    8 * 2 = 16 = The fifth term of the series

    16 * 2 = 32 = The sixth term of the series

    32 * 2 = 64 = The seventh term of the series

    64 * 2 = 128 = The eight term of the series

    Therefore, the 9th term of the series = 128 * 2 = 256.
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